The **train **was going at the speed of 1m/s on the **bridge**.

The length L of the **bridge **is 450m.

The length B of the **train **is 150m.

After entering the bridge,

The last wagon comes out after it has passed ten minutes.

So, the speed of the train can be found out by using the **formula**,

**Speed = Total Distance/total time**

Here, total time is 10 minutes,

We know,

One minute = 60 seconds

10 minutes = 10×60 seconds.

**Total time** = 600 seconds.

Total** distance travelled** by the train is (L+B) when it comes out from the bridge,

So, putting all the values,

Speed = (450+150)/600

Speed = 600/600

Speed = 1m/s.

So, the speed of the train is 1m/s.

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Jenny experiences an average downward force of 441 N anywhere she goes on Earth. Calculate her mass

**Answer:**

Given,

Force = 441 N

mass = ?

Keep in mind that acceleration due to gravity is constant 10m/s.

Force = mass × acceleration due to gravity

mass = Force / acceleration due to gravity

m = 411 N /10m/s

m = 41.1 kg

Therefore her Jenny mass is **41.1 ****kg**.

What is the resistance (in Ω) of a 17.5 m long piece of 17 gauge copper wire having a 1.150 mm diameter?

In order to calculate the resistance of this wire, we can use the formula below:

[tex]R=\frac{\rho d}{A}[/tex]Where p is the resistivity, d is the length and A is the cross-sectional area of the wire.

The resistivity of the copper is 1.72 * 10^-8 ohms*m, so we have:

[tex]\begin{gathered} R=\frac{1.72\cdot10^{-8}\cdot17.5}{\frac{\pi\cdot(1.15\cdot10^{-3})^2}{4}}\\ \\ R=\frac{30.1\cdot10^{-8}\cdot4}{\pi\cdot1.3225\cdot10^{-6}}\\ \\ R=\frac{120.4\cdot10^{-8}}{4.1547563\cdot10^{-6}}\\ \\ R=28.98\cdot10^{-2}\text{ ohms}\\ \\ R=0.2898\text{ ohms} \end{gathered}[/tex]Which of the following examples is NOT an example of energy transfer?bringing water to a boilba boat being accelerated by the force of the enginecrain falling from a clouddwaves in the ocean

Rain falling from a cloud is not an example of energy transfer.

A converging lens has a focal point of 3.93 cm. If you place an apple 19.24 cm away from the lens, where would the image be formed? Submit your answer in meter.

**Given**

The focal length , f=3.93 cm

The object distance, u=-19.24cm

**To find**

The image distance

**Explanation**

By lens formula we have,

[tex]\begin{gathered} \frac{1}{v}-\frac{1}{u}=\frac{1}{f} \\ \Rightarrow\frac{1}{v}-\frac{1}{(-19.24)}=\frac{1}{3.93} \\ \Rightarrow\frac{1}{v}=0.202 \\ \Rightarrow v=4.95cm=0.0495\text{ m} \end{gathered}[/tex]**Conclusion**

The image distance is **0.0495 m**

Can an object have a net negative charge of 2.00 x 10^-19

We will have that **as long as the object is a conductor it will be able to have a net negative charge of 2.00*10^-9 C**.

Given 2 concentric wheels; what weight will an applied force FA of 40.0N down and tangent to the 18.0 cm radius wheel will balance an unknown weight tangent and down on the 10.0 cm radius wheel? Draw the situation

The given problem can be exemplified using the following diagram:

We will determine the magnitude of the force "F" that will balance the concentric wheels.

To do that we will add the torques produced by the forces. If the torque is counterclockwise we will set it a positive and if it is clockwise it will be negative.

[tex]T_{40}-T_F=0[/tex]Where:

[tex]\begin{gathered} T_{40}=\text{ torque produced by the 40 N force} \\ T_F=\text{ torque produced by the unknown force. } \end{gathered}[/tex]The sum of toques adds up to zero because we want to determine the force "F" when the system is in equilibrium.

Now, we substitute the formula for the torques:

[tex]F_{40}r_{18}-Fr_{10}=0[/tex]Where:

[tex]\begin{gathered} r_{18}=\text{ 18 cm radius} \\ r_{10}=\text{ 10 cm radius} \end{gathered}[/tex]Now, we solve for the force "F":

First, we will add "Fr10" to both sides:

[tex]F_{40}r_{18}=Fr_{10}[/tex]Now, we divide both sides by r10:

[tex]\frac{F_{40}r_{18}}{r_{10}}=F[/tex]Now, we plug in the values:

[tex]\frac{(40N)(18\operatorname{cm})}{10\operatorname{cm}}=F[/tex]Solving the operations:

[tex]72N=F[/tex]Therefore, the required force is 72N.

A flowerpot falls from a window sill 34.6 m

above the sidewalk.

What is the velocity of the flowerpot when

it strikes the ground? Choose upwards to be

the positive y direction. The acceleration of

gravity is 9.81 m/s²

The **velocity**of the flowerpot when it strikes the ground is 26.04.

What is **velocity.**

**velocity** is the prime indicator of the position as well as the rapidity of an object. It can be defined as distances covered by an object in unit of the time. **velocity **can defined as the displacement of the object in unit of the time .

Sol- As we know when the object is simply falls it's initial **velocity **is 0.

Therefore u=0

Given question is flowerpot traveled 34.6 before striking the ground.

Therefore s=34.6

We have to find v?

v^2= u^2+2gs

v^2= 0+2gs

v=√2gs

v=√2×9.81×34.6

v=26.04

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A car of mass 1101 kg traveling at 18.39 m/s collides and sticks to a car with a mass of 1050 kg initially at rest. What is the resulting velocity of the two cars right after the collision, assuming that there's no friction present?

Answer: **the resulting velocity of the two cars right after the collision is 9.41 m/s**

Explanation:

The formula for calculating momentum is expressed as

momentum = mass x velocity

According to the law of conservation of momentum, initial momentum = final momentum

The formula for initial momentum is

m1u1 + m2u2

where

m1 = mass of first car

u1 = initial velocity of first car

m2 = mass of second car

u2 = initial velocity of second car

From the information given,

m1 = 1101

u1 = 18.39

m2 = 1050

u2 = 0 because it is at rest

Initial momentum = 1101 x 18.39 + 1050 x 0 = 20247.39

Since the cars stick together after collision, they would have a common velocity, V. Thus,

final momentum = (m1 + m2)V

final momentum = (1101 + 1050)V = 2151 V

Thus,

20247.39 = 2151 V

V = 20247.39/2151

**V = 9.41**

**the resulting velocity of the two cars right after the collision is 9.41 m/s**

Set the cannon to have an initial speed of 25 m/s. For which situation do you think the cannon ball will be in the air for the longest time: if it is set at a 25-degree angle, or if it is set at a 35-degree angle?

Question 5 options:

25 degree

35 degree

The cannon ball will travel the **highest distance **when the angle of projection is **35 degrees**.

The** maximum height** reached by a projectile is calculated using the following formula.

H = u²sin²θ/2g

where;

u is the initial velocity of the projectile θ is the angle of pojectiong is acceleration due to gravitywhen the angle of projection is 25 degrees;

H = (25² (sin 25)²) / (2 x 9.8)

H = 5.7 m

when the angle of projection is 35 degrees;

H = (25² (sin 35)²) / (2 x 9.8)

H = 10.5 m

Thus, the cannon ball will travel the **highest distance **when the angle of projection is **35 degrees**.

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A tetherball leans against the smooth, frictionless

post to which it is attached (Figure 1). The string is

attached to the surface of the ball such that a line

along the string passes through the center of the

ball. The string is 1.40 m long, and the ball has a

radius of 0.110 m with mass 0.280 kg.

After thoroughly calculating we have come to find that, the **tension **in the **string **is 2.752 N

In physics, **tension **is defined as the pulling force transmitted axially by a **string**, cable, chain, or other similar object, or by each end of a rod, truss member, or other similar three-dimensional object.

**Tension **can also be defined as the action-reaction pair of forces acting at each end of the aforementioned elements. Compression's opposite, **tension**, is possible.

We know that

**Tension **= (Mass × gravity) / cos∅

Here given that

Mass = 0.280kg

Gravity = 9.8 m/s²

∅ = 4.2°

Lets substitute the values and we get

**Tension **= (280g × 9.8 m/s²) / cos4.2°

**Tension **= 2.752 N

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Full question

A tetherball leans against the smooth, frictionless

post to which it is attached (Figure 1). The string is

attached to the surface of the ball such that a line

along the string passes through the center of the

ball. The string is 1.40 m long, and the ball has a

radius of 0.110 m with mass 0.280 kg. What is the

tension in the string?

What is the acceleration of a car,

moving along a straight line, that

increases its velocity from 0 to 15

m/s in 10 s?

acceleration = change of velocity / time interval

so for your problem we have

A=15/10

A=1.5m/s

so for your problem we have

A=15/10

A=1.5m/s

A 5.9 x 104-kg space probe is traveling at a speed of 14000 m/s through deep space. Retrorockets are fired along the line of motion to

reduce the probe's speed. The retrorockets generate a force of 1.4 x 104 N over a distance of 3700 km. What is the final speed of the

probe?

**Answer:**

there are 6 circles and 2 triangles. what is the simplelest ratio of triangles to circles

To get a flat, uniform cylindrical satellite spinning at the correct rate, engineers fire four tangential rockets as shown in the figure (Figure 1). Suppose that the satellite has a mass of 1300 kg and a radius of 4.8 m , and that the rockets each add a mass of 250 kg.

a) What is the steady force required of each rocket if the satellite is to reach 46 rpm in 7.0 min , starting from rest?

The **steady force** required of each rocket is **27,875 N.**

The **steady force** required by each rocket along the circular path is calculated as follows;

F = ma

where;

m is the mass of the each rocketa is the centripetal acceleration of each rocketThe **centripetal acceleration** of each rocket is calculated as follows;

a = ω²r

where;

ω is the angular velocity of the rocketr is the radius of the circular pathω = 46 rpm = 46 rev/min x 2π rad/rev x 1 min/60s = 4.82 rad/s

t = 7 min = 7 x 60 s = 420 s

a = ω²r

a = (4.82²) x 4.8 m

a = 111.5 m/s²

The** steady force** is calculated as follows;

F = ma

F = 250 x 111.5

F = 27,875 N

Thus, the steady force required of each rocket is determined by applying the concept of **centripetal force**.

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free fall is any motion of a body where is the only force acting upon it

free fall is any motion of a body where is the only force acting upon it is gravity.

Pls answer. Will rate 5 start and give a Thanks or Brainliest.

What are the characteristics of the Sun? (Select all that apply.)

Group of answer choices

The Sun is the center of our solar system and radiates energy.

The Sun is a medium-sized star compared to other stars in the universe.

The Sun has planets and dwarf planets that orbit it.

The Sun is composed of helium and hydrogen.

The Sun is near the end of its life.

The** Sun** is composed of** helium** and hydrogen. Option C.

The **photosphere** chromosphere and **corona** are all part of the Sun's atmosphere. Although the corona is sometimes called the solar atmosphere it is actually the sun's upper atmosphere. The sun's atmosphere includes features such as sunspots, coronal holes, and solar flares the sun is a star.

It's a huge spinning ball of hot gas. The **sun **is like a star in the night sky. Because we are so close it appears much larger and brighter than other stars. The sun is the center of the solar system and accounts for most of the mass of the **solar system**. Compared to the billions of other stars in the universe, the sun stands out. But for the Earth and the other planets orbiting around it, the Sun is a powerful focal point.

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Which statement below best describes how scientists explain gravity's role in the formation of

our Solar System? and Why?

A. The combined gravitational attraction between our planets was so large that it pulled the

Sun away from a nearby star cluster into the center of our Solar System.

B.The eight planets in our Solar System were originally orbiting a nearby star, and the Sun's

gravity was large enough to pull those planets into orbit around the Sun.

C. Due to the expansion of neighboring solar systems, the gravitational attraction of our

planets to those solar systems forced the formation of the planets around our Sun.

D.As the Sun was forming, the force of gravity caused surrounding dust grains to collide and

stick together, forming dust granules into increasingly larger bodies that became planets.

D. As the Sun was forming, the force of **gravity** caused surrounding dust grains to collide and stick together, forming dust granules into increasingly larger bodies that became **planets**.

About 4.6 billion years ago, the Solar System was a cloud of dust and gas known as the** Solar Nebula**.

Gravity is the force that pulls a** body **toward the center of the Earth or any other physical body that has mass.

Therefore "As the Sun was forming, the force of gravity caused surrounding dust grains to **collide** and stick together, forming **dust granules **into increasingly larger bodies that became planets", best describes **scientists** explain gravity's role in the formation of our Solar System.

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What is the mass of a 37.0 Nweight?m =?] kgEnter

**Answer:**

**m = 3.8 kg**

**Explanation:**

The weight can be calculated as follows:

[tex]W=m\cdot g[/tex]Where m is the mass and g is the gravity. So, replacing the weight by 37 N and the gravity by 9.8 m/s², we get:

[tex]37\text{ N = m}\cdot9.8m/s^2[/tex]So, solving for m, we get:

[tex]\begin{gathered} \frac{37}{9.8}=\frac{m\cdot9.8}{9.8} \\ 3.8\operatorname{kg}\text{ = m} \end{gathered}[/tex]Therefore, the answer is m = 3.8 kg

Which of the Figures correctly represents the force diagram to solve the problem?

**ANSWER**

Figure 1

**EXPLANATION**

We want to identify the correct force diagram acting on the object on the inclined plane.

When an object is moving on an inclined plane, there are four forces acting on it:

1. Friction force, Fr

2. Normal force, FN

3. Component of weight acting parallel to the inclined plane = Wsinθ

4. Component of weight acting perpendicular to the inclined plane = Wcosθ

Therefore, the correct option is **Figure 1**.

If the lines in problem below, have a resistance of 100-Ω, calculate the change of voltage along each line. We are asked to determine the current given the power and the voltage. To do that we will use the following formula:P=IVWhere:P= powerI= currentV= voltageNow, we divide both sides by "V":PV=INow, we convert the power from "kW" to "W" using the following conversion factor:1kW=1000WMultiplying by the conversion factor we get:200kW×1000W1kW=200000WNow, we plug in the values in the formula:200000W48000V=ISolving the operations:4.2A=ITherefore, the current is 4.2 Amp.

Resistance 100

Current 4.2A

Based on the information of the last point, we know the current and now we have the resistance. With these two numbers we can calculate the drop of voltage generated by the resistance.

Is important to highlight that we asume the same current for each line because the current is constant in all the parallel lines.

[tex]\begin{gathered} V=IR \\ V=100\Omega\cdot4.2A \\ V=420V \end{gathered}[/tex]How many hours would it take a plane to fly 1,500 miles if it was moving at a constant speed of 300 miles/hour? Include units!

Best answer gets brainliest!

Answer:

5 hours

Explanation:

distance/speed= time

1500/300= 5

I am not sure if this is true or false. Please help

We have the formula of Newton's second law

[tex]F=ma[/tex]Where F is the force, m is the mass and a is the acceleration.

If we isolate the acceleration

[tex]a=\frac{F}{m}[/tex]As we can see if the mass increases the acceleration will decrease

Therefore the answer is **FALSE**

The oscilloscope can be used to measure AC frequency by counting the number of _____________ per unit time.A. PeaksB. Complete wavesC. ValleysD. Partial wavesJust please give me the answer, no explanation.

The **oscilloscope **can be used to measure AC frequency by counting the number of **complete waves** (Option B).

An **oscilloscope **is a tool used to measure voltage by observing how the electrical signals from different types of waves may change over a given unit or period of time, which is useful to monitor a client's heartbeat and brain waves.

Therefore, with this data, we can see that an oscilloscope is a device used to measure waves (in this case **brain waves**) in order to indicate a given outcome associated with electrical signals.

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2. A saucepan containing 2 kg of water is heated. 400 kJ of energy is transferred. Calculate the temperature

increase of the water.

The specific heat capacity of water is 4200 J/kg °C. Give your answer to four significant figures.

The **temperature increase** of the 2 kg water if 400 kJ of energy is transferred is 47.62 °C

**q = m c ΔT**

q = Heat

m = Mass

c = Specific heat

ΔT = Change in temperature

q = 400 KJ

m = 2 kg

c = 4200 J/kg °C

ΔT = q / m c

ΔT = 400 * 10³ / 2 * 4200

ΔT = 47.62 °C

The quantity of heat energy required to change the temperature of particle by 1 °C is known as **heat capacity**. Specific heat capacity is the heat capacity is calculated for 1 gram of matter.

Therefore, the temperature increase of water is **47.62 °C**

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A 55 kg skater rolls along a U-shaped half pipe starting at rest from a height of 15 m. The skater rolls to the other side of the half pipe at a height of 12 m before stopping. What is the work done by friction?

The **work done** by** friction i**s -1617 J

**Work done** is the product of force and distance moved in the direction of the force.

**Friction** is the opposition to motion between two surfaces

From the lwa of conservation of energy, the **work done **by **friction,** W equals the change in potential energy of the skater, ΔU.

So, ΔU = W

mgΔh = W

mg(h₂ - h₁) = W where

m = mass of skater = 55 kg, g = acceleration due to gravity = 9.8 m/s², h₁ = initial height of skater = 15 m and h₂ = final height of skater = 12 m.So, substituting the values of the variables into the equation for the **work done**, we have

W = mg(h₂ - h₁)

= 55 kg × 9.8 m/s²(12 m - 15 m)

= 55 kg × 9.8 m/s² × (-3 m)

= 539 kgm/s² × (-3 m)

= -1617 J

So, the **work done** is -1617 J

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When light is reflected, the incident rays are bent and change direction.

**Given**

When light is reflected, the incident rays are bent and change direction

**To find**

Whether the given statement is true

**Explanation**

When we flash a light on the mirror, the light changes its direction and move in another way. So the incident light changes direction when reflected

**Conclusion**

The given statement is **TRUE**

An egg test dummy is fitted with a helmet, sealed in a plastic bag, and attached to a swing with a clamp. These items have a mass of 0.090 kg. This mass is pulled back to a height of 0.55m. The mass is then released and allowed to swing down and collide with a cement block. What is the speed of the mass at the moment before impact?

The **speed** of the mass at the moment before impact is** 3.28 m/s.**

**What is the final speed of the egg?**

The **speed** of the mass at the moment before impact is calculated from the principle of conservation of energy as shown below.

K.E(bottom) = P.E(top)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

v is the speed of the egg before the impacth is the height of the fall of the eggSubstitute the given parameters and solve for the **speed** of the egg before the impact.

v = √2gh

v = √(2 x 9.8 x 0.55)

v = 3.28 m/s

Thus, the **speed** of the mass at the moment before impact is determined by applying the principle of conservation of energy.

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. In one day, the temperatures of a desert range from 110°F in the afternoon to 55°F at night. What

is this temperature range on the Kelvin scale?

**Answer:**

30.5555°K

Can be rounded to 30.56°K

**Explanation:**

The relationship between °C and °K is

°K = °C + 273.15

To convert °F to °K, first convert °F to °C and then add 273.15

°C = (°F - 32) x 5/9

So combining the two conversions we get

°K = (°F - 32) x 5/9 + 273.15

55°F = (55-32) x 5/9 + 273.15 = 285.9278°K

110°F = (110-32) x 5/9 + 273.15 = 316.4833°K

Temperature range in Kelvin scale

= 316.4833°K - 285.9278°K = 30.5555°K

A. Thermal to Chemical to Electrical to MechanicalB. Mechanical to Chemical to Electrical to Thermal C. Electrical to Chemical to Mechanical to ThermalD. Chemical to Thermal to Mechanical to Electrical

**Given:**

Coal-fired power plant

**Required:**

Energy transformation in coal-fired power plant.

**Explanation:**

Coal has chemical energy.

When the coal is heated, the chemical energy transforms into thermal energy.

Thermal energy is used to rotate the blade of the turbine, so thermal energy transforms into mechanical energy.

The rotating blades produce electricity, so mechanical energy transforms into electrical energy.

**Final Answer: **The energy transformation of a coal-fired power plant is chemical to thermal to mechanical to electrical.

You can buy 50 rolls of toilet paper for $12.50. Write a ratio showing the unit rate of rolls per $1.

**Answer**:

**Explanation**: We need to find the unit rate or rate of rolls per **$1**:

To find the number of rolls per one dollar we simply need to take the ratio of the two as follows:

[tex]\frac{50R}{12.50D}\Rightarrow(1)[/tex]Simplifying **(1) **gives the answer as follows:

The answer therefore is:

[tex]\text{4 rolls per \$1}[/tex]how can earthquakes be more destructive than tsunamis

Buildings can be destroyed by **earthquakes **or knocked down, trapping **people** underneath.

Only regions close to the water are susceptible to **tsunamis**, but anybody may be affected anywhere by **earthquakes**. Buildings can be destroyed by earthquakes or knocked down, trapping people underneath. Uneven surfaces and **damaged roadways** can result from the** shifting **and** cracking **of the Earth during earthquakes. When two chunks of the ground abruptly slide past one another, an earthquake results. The fault or fault plane is the area where they slide. Sudden movement along Earth's fault lines causes earthquakes. The motion releases "**elastic strain**" energy that has been accumulated in the form of **seismic waves**, which travel through the Earth and cause the earth to** tremble**.

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Balance the chemical reactionusing an atom inventory.What is the coefficient foraluminum?[?]AI + [ ?]Cl [?]AICI3
According to the map, what is the name of the body of water to the north of Bunker Hill? A. Mystic RiverB. Atlantic OceanC. Charles River
Question 3 of 10People moving to the United States from ____ were typically excluded from American culture.OA. southern EuropeB. western Europe C. England D. East Asia
10. What advice does Mr. Webb give George about married life?
Convert compressions to simplified faction or integer. If its not a real number, enter None
A report this week said that herschel walker, the republican nominee in a competitive senate race, paid for an abortion in 2009. In which state is walker running?.
Even on his deathbed, Socrates felt that:
Circle O has a circumference of 88 cm.Circle O has a radius length of r.What is the length of the radius of the circle?
Elijah and his brother ran a race. Elijah reached the finish line in 60.26 seconds and his brother reached the finish line 6 seconds later. How long did it take Elijah's brother to run the race?
ABC is shown . D is a point on AB,AC =7, AD=6, and , BC=18.
Find the solution of the system of equations.6x 3y = -303x 6y = 12
Help I dont understand whats happening
8. Which is an abiotic factor of an ecosystem?a) fernsb) waterc) birdsd) fishFossvo
according to surveys what is the third largest expense of a typical american consumer
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donuts are sold in bags and cartons. a bag holds four donuts and a carton holds 10 donuts. tom buys b bags of donuts and c cartons of donuts. he buys a total of t donuts. write down a formula for t in terms of b and c
COLOR BY NUMBERNET FORCEDate:Per:Directions: Answer each question by circling the correct choice. After you have completed all of thequestions, color the picture using the assigned colors.QuestionChoice A1. The sum of all forces acting on anobject is known as...2. Which of the following is acharacteristic of a balanced force?3. Which of the following is acharacteristic of an unbalanced force?4. Which of the following representsbalanced forces?5. Which of the following representsunbalanced forces?6.7.8.9.10.10N147N7N[orange]Directions: Calculate the net force in the questions below.120N16N3N 74N4N5N14N5N50N7Napplied force[purple]equal in size,opposite in direction[red]equal in size,opposite in direction[sky blue]7N7N12N to the left[orange]A) ON [red]B) 7N, right[purple]7N125N to the right[green]C) 28N, right[green]C) 2N, left[blue][purple]A) 2N, right[red]3N7N to the left[red-orange]B) 12N, right[purple]Name:Choice Bnet force[black]causes a changein the directionof an object[sky blue]does not cause achange in the motionof an object[green]11N[sky blue]5N[purple]11NSN11N to the left[yellow]125N to the left[sky blue]21N to the right[orange]A) 45N, right [brown]B) 35N, right [orange]C) 40N, right [yellow]B) Dog B [yellow]C) Dog C[green]Choice Cnormal force[green]causes a changein the motion ofan object[orangelcauses a changein the motion ofan object[purple]8N4N[orange]2N 2N[yellow]21N to the left[blue]170N to the right[pink]11. Two students kick a soccer ball at the same time.Student A kicks the ball with a force of 80N to theright. Student B kicks the ball with a force of 45N tothe left. Calculate the net force.1N to the left[yellow-green12. Three dogs are pulling on a stuffed animal. DogA pulls with a force of 150N to the north. Dog B pullswith a force of 150N to the south. Dog C (a muchsmaller dog) is pulling to the east with a force of40N. Which dog will win the toy?A) Dog A [red-orange]Morpho Science
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